+1 EndDate + 23:59:59. DATEDIFF(interval, date1, date2) Parameter Values. 8494441'. Another example is to get the month of. startdate or. Here is example with 23 hours difference: select CONVERT (VARCHAR, DATEDIFF (dd, '2018-04-12 15:54:32', '2018-04-13 14:54:32')) + ' Days ' + CONVERT (VARCHAR, DATEDIFF (hh, '2018-04-12 15:54:32', '2018-04-13 14:54:32') % 24) + ' Hours ' But the. Another example using the MONTHS_BETWEEN function in Oracle/PLSQL is: MONTHS_BETWEEN (TO_DATE ('2003/07/01', 'yyyy/mm/dd'), TO_DATE ('2003/03/14', 'yyyy/mm/dd') ) would return 3. For example, between those dates: "03/03/2020 - 06/06/2020" I need something like "(03,04,05,06)". g for me the max dates is 1399, You can calculate this with select count(*) from sys. 997268. Then, we need a 2-digit month string. Use a built-in function to “move”. user637544 Jun 1 2009 — edited Jun 1 2009. A) Get the difference in months of dates on the same day. Assuming you are asking about MySQL the below query will provide you with the remaining time required. The MONTHS_BETWEEN () function is used to get the number of months between dates (date1, date2). 5 days to a given date. If you really want 'datediff' in your database, you can just do something like this: Now, i just create a view to demonstrate with: SQL> select datediff ( 'ss', d1, d2 ) seconds from temp_view; SECONDS6269539. The DATEDIFF function does not calculate the difference in months based on days. [proc_datediff] ( @date datetime ) as begin DECLARE @diff varchar(70) DECLARE @tmpdate datetime, @years int, @months int, @days int SELECT @tmpdate = @date SELECT @years =. Adds a specified time interval to a DATE value. S is milliseconds in one or up to six digits. datediff (q,start date,end date) i. DATE_FORMAT () Format date as specified. MONTHS_BETWEEN = 1. This expression: to_date(SYSDATE, 'yyyy-MM-dd') doesn't make sense. I would like to select 1 if current date falls between 2 dates through Oracle SQL. For DATEDIFF: date_or_time_expr1 and date_or_time_expr2 can be a date, time, or timestamp. The int data type takes 4 bytes as storage size whereas. The difference between 1st March 2011 and 29th February 2012 is 0. StartDate) AND. 3. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. We are now using NHibernate to connect to different database base on where our software is installed. CASE WHEN GETDATE () = 'first of this month' THEN 'DATE column' between 'first day of last month' and 'last day of last month'. @KanagaveluSugumar - An Oracle DATE always has a year, month, day, hour, minute, and second component. Get Number of Months Between 2 Dates. select (dt1-dt2) * 24 * 60 * 60 from t; dt1-dt2 gives diff in days (eg: 1. current_time() returns the date and time on the database client side. DATEDIFF(date1, date2) Parameter Values. In PostgreSQL, you can take the difference in years, multiply by 12 and add. Two dates to calculate the number of days between. Date. , year, quarter, month, day, hour, minute, second), startdate is the starting date or time, and enddate is the ending date or time. buf 1 declare 2 total_days integer; 3 total_weeks integer; 4 remaining_days integer; 5 begin 6 total_days := date '2014-12-16' - date '2014-12-01'; 7. Viewed 110k times 49 I have a table with following structure. The following shows the syntax of the syntax of the NEXT_DAY() function:. DATE_ADD () Add time values (intervals) to a date value. Share. Example 2. hh is a two digits of hour (00 through 23). date_open are both of type date, you can simply subtract them to get a difference in days. 利用日期间的加减运算. 997268 (0 year + 365/366 years) So, in summary, the output (in DECIMAL (7,6)) from the above two examples would be: 1. EXE. Taking out our calculator, we see that 30 minutes equals 1day/24hours*0. End date will be sysdate. Voila! You've the the last day of the month containing your reference point in time. Which leads me to believe that it is treating February. Month and day of the year don’t appear to be factored into the equation. sql. 2425. CREATE OR REPLACE FUNCTION dateDiff ( p_dt1 IN DATE, p_dt2 IN DATE ) RETURN NUMBER IS BEGIN RETURN p_dt1 - p_dt2; END; It's not obvious, though, what benefit you derive from doing this rather than simply. It uses month boundaries as calculating the difference in months, with each change in calendar month adding one to the answer. parse_datetime(string, format) → timestamp with time zone. Fractions are allowed; you can add 2. Start date will. SELECT TIMESTAMP_FORMAT (“2021-03-15”, “%Y”) as “Year of the date”; TO_DATE. Viewed 417k times 57 I would. DECLARE @ADate DATETIME SET @ADate = GETDATE () SELECT DAY (EOMONTH (@ADate)) AS DaysInMonth. I am looking for a way to implement the SQLServer-function datediff in PostgreSQL. The following query selects all rows with a date_col value from within the last 30 days: . 7 Date and Time Functions. @Mohit224 - If you are saying that you want to ignore any fractional part of a year, then you. VALID_FROM_DTTM between DATEADD(m,-1,DATEADD(m, DATEDIFF(m,0,GETDATE()),0)) and. sql-server-2008. DATE_SUB () Subtract a time value (interval) from a date. 5 = 0. The two date fields are "timestamp" format (date and time). Follow answered Aug 3, 2011 at 18:51. In addition, with DATEDIFF () the column is an argument to the function. *Subtract the two date values, divide by (60 seconds * 60 minutes *. Select between two months. enddate,e3. The value returned is always of data type DATE, even if you specify a different datetime data type for date. DiffYears Returns the difference in years between two dates. mm is a two digits of minute (00 through 59). Select name,surname,datediff(YY,birthDate,getdate()) as age from students order by age. DateDiff ( date1, date2, date_part) パラメータ 説明; date1. If you want to confirm, simply run this. The resulting column will be in INTERVAL DAY TO SECOND. Multiply it by seven to give the number of weeks spanned. Basic WHERE (Actual,. 1. We’re calculating months of service in this example. Share. 1. Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. select. Date 1: 10th March 2011. Next to calculate a month of services in a company by a user we would use ‘m’ to calculate the difference value. hh is a two digits of hour (00 through 23). DATEDIFF_BIG () is a SQL function that was introduced in SQL Server 2016. Current Date/Time. 16. How best can this be written? I need to use this in a where clause on DI Studio. g. The DATEADD() function adds or subtracts a specified time interval from a date. DateDiff(“m”, Fields! starting date. The Question asked for "6 months from the system date". Difference of two dates in months. ie if the month when the query is run is march 2013. Oracle PeopleSoft Tips and Tricks. When the reporting date month is the same as the target month you can get a round up To get the number of month or day, you change the first argument to month or day as shown below: Notice that the DATEDIFF () function takes the leap year into account. SQL Server ignores that this is just one day. 9. I want to calculate the current Age from Date of Birth in my Oracle function. dividing by 365. The datediff function returns the difference between two specified dates in the time units that you specify: years, quarters, months, weeks, days, hours, minutes, or seconds. If date1 and date2 are either the same days of the month or both last days of months, then the result is always an integer. Only 10+ years later - here's a db<>fiddle which demonstrates the difference between subtracting a date from a date (e. I say ALL months as months can have 28 days (29 in a leap year), 30 days and 31 days which is why I wouldn't simply calculate the days between two dates. The DATEPART () function returns an integer value that represents a specified part of the date of a given date. There are two methods to achieve this. Expressions that return a value of any of the following built-in data types: a date, a timestamp, a character string, or a graphic string. Any help would be appreciated. Hi team i need to get the exact month differences between two dates i am using oracle sql for my project . SELECT to_char ( your_date_column, your_format_mask ) FROM your_table ORDER BY your_date_column. adddate addtime curdate current_date current_time current_timestamp curtime date datediff date_add date_format date_sub day dayname dayofmonth dayofweek dayofyear extract from_days hour last_day localtime localtimestamp makedate maketime. *You may also use the DATEDIFF function. DATEDIFF(datepart, startdate, enddate) Parameters. 679 seconds. Modified 1 year, 8 months ago. 0. Access Function: DateDiff ("m",PAID_DATE,STATIC_DATE) AS Months_Between. Push out all due dates by one week. Let’s factor it in! First, we will take the person’s birthday and will use the DATEADD( ) function. You can include Oracle hints in PeopleSoft Query expressions as long as you adhere to the following rules: Expressions containing a hint must begin with /*+ . A) Get the difference in months of dates on the same day. If you omit fmt, then date is rounded to the. Add a number of months (n) to a date and return the same day which is n of months away. 9. Sure, the query depends on which database you’re using (Oracle, SQL Server, MySQL, etc). Date > T1. 1. It should be 24 months. @WernfriedDomscheit YYYY-MM-DD is not a date it is just a formatted string. 005479 0. For the last row return the calculated date. Purpose MONTHS_BETWEEN returns number of months between dates date1 and date2. We would like to show you a description here but the site won’t allow us. Table 9. Oracle offers its own solution, although does not have the DATEDIFF function. Share. Syntax. Each Standard calendar week is defined to start on Sunday and it spans 7 days. ADD_MONTHS returns slightly different results than DATEADD used with a MONTH component:. 5. One option that avoids needing to add EndDate + 23:59:59. For example, only one set of /*+ */ is allowed. This works because you have no issue with months and years or one-digit vs. For a baby born 28-Feb-17, properly calculated they turn 1 years old on 28-Feb-18 - their next birthday. SELECT date_part ('month',age ('2016-06-30', '2018-06-30')) The result of this query is 0. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. The number is the number of seconds elapsed since midnight, January 1, 1970. Improve this answer. this will gives you the last 3 month date (from 1st of the month) WHERE date_column >= DATEADD (MONTH, DATEDIFF (MONTH, 0, GETDATE ()) - 3, 0) you have 3 date. 指定した日付の差異。次の値が有効です。 DD: 差異を日数で計算します。. 取得一季中的第一天：. CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL. Dateadd function is not working in oracle SQL. What this allows you to do is pass in two TIMESTAMP or DATETIME values (or even DATE as MySQL will auto-convert) as well as the unit of time you want to base your difference on. 01/31/2021: Introduced in SQL Server 2012. date_from, evnt. Month difference between two dates in sql server. Using datediff in oracle. Return the current time. Asked 1 year, 8 months ago. SQL Query with Dates. Not all of the expressions described at the URL are supported in NetSuite. ;-). )CREATE OR REPLACE FUNCTION datediff (p_what IN VARCHAR2, p_d1 IN DATE, p_d2 IN DATE) RETURN NUMBER /* Updated to reflect current database and PL/SQL functionality */ AS BEGIN RETURN (p_d2 - p_d1) * CASE UPPER (p_what) WHEN 'SS' THEN 24 * 60 * 60 WHEN 'MI' THEN 24 * 60 WHEN 'HH' THEN 24 ELSE NULL END; END;If this solve your problem, here's the sql server syntax, just replace the variable @yourDate with your column name. add_months (date,n) Returns the date that corresponds to date plus the number of months indicated by the integer n . If the days of the month are both the last day of the month (e. 33 shows the available functions for date/time value processing, with details appearing in the following subsections. Modified 8 years ago. Oracle SQL - CASE in a WHERE clause. Third, the more verbose method. A number representing the input date between January 1, 1970 and Dec 31, 2037. 25) This seems to be another common approach - and was also given in a comment on my question. ( See. you can check against last 90 days. The fact that the function returns an integer number of months both when the days of the month are the same (e. Get the number of months between two dates. . select DATEADD(MONTH,1350,0) will give 2012-07-01 00:00:00. then if day/month of dob is less than. Modified 3 months ago. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). EXE. I guess I did not read the question in depth. The NEXT_DAY() function accepts two arguments:. Hi tom, I want day, month, minute and years difference everyting in seconds. 41935483870968. Fractions are allowed; you can add 2. I have a table where PurchasedDate is maintained. last_day (feb) to last_day (mar) is also commonly accepted as a "month". Share. SELECT * FROM TABLE_NAME WHERE DATEADD (DAY, -90, GETDATE ()) between txtFromDate and txtToDate. e. 1. Here's how it does this: First the DATE function creates the date, 5/1/2016. Here is an example that uses date functions. 2. The first one involves getting the difference in days and then converting it to 'x year y month z days'. sql. Let’s see a few examples of SQL subtract date from the DATEADD function: In the below example, we are adding one month to the existing date ‘20220730’. DP_MONTH returns the distance between the months capturing the input dates. If date1 is earlier than date2 , then the result is negative. SELECT DATEADD (month, 1, '20220730'); The below DATEADD will add 1 year to the provided date value, the year changed from 2022 to 2023. The result is formatted according to the Format parameter. In SQL Server 2012 you can use EOMONTH (Transact-SQL) to get the last day of the month and then you can use DAY (Transact-SQL) to get the number of days in the month. The result is formatted according to the Format parameter. We’re calculating months of service in this example. Factor by 24 to get hours, 24*60 to get minutes, 24*60*60 to get seconds (that's as small as dates go). Also, "month" is an arbitrary concept when applied to a certain number of days in an interval. 997 All results I use in BETWEEN operator, therefore last 'day' should include last millisecond of the very day. This works as Oracle will perform an implicit cast (using TO_TIMESTAMP( time, format_mask )) using the session parameter. startdate: The first date or datetime value. select sysdate - date '2022-01-03' as delta from dual; The resulting value on the day I am running this is 37. So, there’s. , SYSDATE - pr. 3. The value returned is always of data type DATE, even if you specify a different datetime data type. startdate, DATEDIFF(DAY,e1. date_part is the part of. 15 minutes. You could always create your own custom function in the module: Function MonthDiff (startdate, enddate) ' return number of months between two dates. I see that marked final solution is not correct always. Arguments. The Question asked for "6 months from the system date". e it takes the quarter in which the start date exists and subtracts it from the quarter in which the end date exists. TotalDays([EndDate]-[StartDate])/30 . For both DATEDIFF and minus sign: Output values can be negative, for example, -12 days. That prevents. , NextDate, DATEDIFF("D", Date, NextDate) FROM ( SELECT ID, AccountNumber, Date, ( SELECT MIN(Date) FROM YourTable T2 WHERE T2. SELECT DATEDIFF (second, '2019-12-31 23:59:59', '2020-01-01 00:00:00'); A value of 1 is returned because the boundary of seconds is crossed once. LeapYear Returns one (1) if the specified year is. . For example, from 2/10 to 3/10 is considered one month, and from 2/10 to 3/15 is also. 15 between 2 values that are 1 year, 1 month and 15 days apart. SYSTIMESTAMP). I was given code via an SR but it doesn't work (I'm able to save the code but when I try to look at the sample data, it just says "error"). select emplid from. Returns. This is in the manual. Viewed 32k times. Then it would also be helpful to be able to. 0. You may: count the number of 24h elapsed time: day+1 - day = 1 day = 24h. So given Netezza is based on PostgreSQL, so it's AGE function, is equivalent to Snowflake's DATEDIFF, but like PostgreSQL interval it defaults to expressing it in simplified terms of Years/Months/Days. The function INTCK ('MONTH','1feb1991'd,'31jan1991'd) returns –1 because the first date is in a later discrete interval than the second date. The return type is always DATE, regardless of the datatype of date. Function. To calculate the number of days between date1 and date2, you can use either Day of. You cannot mix xdofx statements with XSL expressions in the same context. For instance, select datediff (day,'1 Jan 2000' ,'18 April 2014') / 365. I want to calculate the current Age from Date of Birth in my Oracle function. If you want an integer number of days. DATE_DIFF = 1. In the SELECT list, you want to return a character string that represents the date in your preferred format. 2258064516. answered Oct 19, 2016 at 9:38. DATE_ADD () Add time values (intervals) to a date value. Calculates the difference in days between the two dates. 一重引用符で囲んだ'YYYY-MM-DD[*HH:MI[:SS]]'形式の文字列(*はコロン(:)または空白でも可)、または現在の日付を返す引用符なしの@DATENOW. DATE_FORMAT(): This function formats a specified date as per the format specifier (%e for date, %c for month, %Y for year, and many more). If date1 is earlier than date2, then the result is negative. public static int MonthDiff (DateTime d1, DateTime d2) { int retVal = 0; // Calculate the number of years represented and multiply by 12 // Substract the month number from the total // Substract the difference of the second month and 12 from the total retVal. Thanks for the infoFirst step is to join the tables together such that we get a row for every relevant month that intersects with the start and end dates in your HRAL table. In Oracle, MONTHS_BETWEEN(date1, date2) function returns the number of months between two dates as a decimal number. February 28 and March 31) can lead to unintuitive behavior; specifically, increasing the first date in the pair does not always increase the output value. So, it starts with RIGHT(“00”. 1 Answer. The math is 100% accurate for dates within a couple of hundred years or so. DateAdd. 1970年1月1日から2037年12月31日までの入力日付を示す数値。. PRINT DATEDIFF(Day, 2010-02-20, 2010-01-01) RETURN 20SELECT DATEDIFF (MM,0,GETDATE ()) Add same number of month to date 0 (1901/01/01) SELECT DATEADD (MM, DATEDIFF (MM,0,GETDATE ()),0) Then we will get first day of current month (Current Date or a given date) To get Last Day of Last Month. Thus your AGE ('2019-12-01', '2018-12. This page provides you with the most commonly used Oracle date functions that help you handle date and time data easily and more effectively. You could, of course, write your own function and call that. Syntax:DATEDIFF Examples Using All Options. v_interval := p_end_date - p_start_date + 1; -- calculate total number of days between dates, including start and end dates. See Date and Time Data Types and Functions (Transact-SQL) for an overview of all Transact. SELECT DATEADD(WEEK, DATEDIFF(WEEK,0,GETDATE()),-3) Executes. Using this, I can find the first day of any given month using, but just that month and it does not take into consideration whether it is a business day or not. 0. 58064516129032. date_open are both of type date, you can simply subtract them to get a difference in days. DATE is the main – or rather, original – datatype used in Oracle for holding dates. Java date functions. 5 days to a given date. The age in days between the two dates is either 2 or 3 days, but in one case the DATEDIFF function returns an Int data type. The minus sign is used to compute the difference between two. Funciones comúnmente utilizadas de Oracle: DateDiff devuelve una función personalizada para el intervalo entre dos fechas (Por supuesto, hay otros métodos para lograr, en ORACLE los tipos de fechas se pueden comparar directamente, y finalmente dar ejemplos de métodos). * , dd. Now for testing purposes I need to compare the data for the last say 4 months from the sysdate. Just divide the total by 7 to get the weeks and then calculate the remaining days. DATEDIFF with examples DATEDIFF function accepts 3 parameters, first is datepart (can be an year, quarter, month, day, hour etc. The date argument is a DATE value (or an expression that resolves to a DATE value) that should be rounded. Here is an example that uses date functions. Month([EndDate]) - DateMonth([StartDate]) Regards, Pat29 Answers. – WAMLeslie. select level rn from dual connect by level <= 3; RN 1 2 3. 032258Currently, my code just returns zero on the right side of the decimal place. Select(x => x. Truncate a Date to a Specific Unit of Measure. For formatting functions, refer to Section 9. CASE WHEN a. 1. datediff() is not giving tHe result as I am working in Oracle. I can mention four important functions of MS SQL Server that can be very useful: 1) The function DATEDIFF() is responsible to calculate differences between two dates, the result could be "year quarter month dayofyear day week hour minute second millisecond microsecond nanosecond", specified on the first parameter (datepart):. Asked 7 years, 2 months ago. If I run. If date1 is earlier than date2 , then the result is negative. Month-difference between any given two dates: Have a look at the TIMESTAMPDIFF () function in MySQL. SYSDATE) and subtracting a date from a timestamp (e. Thanks in advance for any help; this has been driving us crazy for a few months now. The month and the last day of the month are defined by the parameter NLS_CALENDAR. Multiply the result of step 1 by 12 to transform it to months 3. End Function. Oracle-compatible TO_CHAR function that can format a timestamp, a number. But your query is giving the last date of previous month. sql. Thus far, we have seen very important SQL date format functions such as DATEPART, DATENAME, YEAR, MONTH, and DAY, with particular emphasis on the DATEADD SQL function and the DATEDIFF SQL function. date_from, evnt. To find the date difference in minutes from the given DateTime values, use the following steps: - First, find the “date_diff” in days and multiply it with “24”. If either expression is a character or graphic string, it must not be a CLOB. January 30, 2004 - 7:26 pm UTC. My DOB- 02-feb-1984 so my age should get as 27 Years 2 months 8 days How to do it. Quarter (rounds up on the sixteenth day of the second month of the quarter) Same day of the week as the first day of the calendar week as defined by the ISO 8601 standard, which is Monday. 8494441'. Admission_Date < ADD_MONTHS (sysdate, -5) which could still use an index on that column, if there is one. Syntax. Move the start date to the next Monday, then add the calculated weeks. txt","contentType":"file"},{"name. Result: 505 rows listed. Subtracting two dates will return if and only if they are the same year, the same month, the same day, the same hour, the same minute, and the same second. SELECT DATEADD ( quarter, DATEDIFF. The syntax for the DATEDIFF function is as follows:. HQL And datediff() Functions. The week (wk, ww) datepart reflects changes made to SET DATEFIRST. MONTHS_BETWEEN(p1, p2) DATEDIFF( MONTH, CAST(p2 AS float), CAST( DATEADD(DAY, ( -CAST(DATEPART(DAY, p2) AS float(53)) + 1 ), p1) AS float)) Round a Date to a Specific Unit of Measure. For example, we can use the DATEPART function to get the day of a given date to determine whether an order was placed on Sunday or not. Viewed 44k times 3 I've got 2 date columns in my table (start_date, end_date). Note that SQL Server DATEDIFF(month, date2, date1) function does not return exactly the same result, and you have to use an user-defined function if you need to fully emulate the Oracle MONTHS_BETWEEN function (see. (Query using SQL server 2005 and 2008 is allowed). Calculate difference between 2 date / times in Oracle SQL. The integer value represents the day and the fractional value represents the. Oracle SQL Hours Difference between dates in HH:MM:SS. This conversion uses the NLS_DATE_FORMAT parameter to decide the format of the output string. EOMONTH (date [,months to add) Returns the last do of the month with an optional parameter to add months (+ or -). select *, cast ( (cast (begin_date as date) - cast (end_date as date) YEAR) as decimal (3,2)) AS year_diff from x. If the year diff has to be counted this way then use: EXTRACT (YEAR FROM date_to) - EXTRACT (YEAR FROM date_from) Just for the log. Here is the synopsis: If using Oracle use the trunc and numtoyminterval functions; if using SQL Server use the datediff function. Oracle GoldenGate add trandata errors. FLOOR (DATEDIFF (DAY, date_of_birth, reference_date) / 365. The dateadd function adds or subtracts a number of specified time units from a given date. select months_between(date '2015-03-19', date '2012-01-06') as month_diff from dual; MONTH_DIFF ----- 38. lastModified and w. ROUND (TO_NUMBER (END_DATE - START_DATE)) 小时：. 0. SQL> select 24 * (to_date ('2009-07-07 22:00', 'YYYY-MM-DD hh24:mi') - to_date ('2009-07-07 19:30', 'YYYY-MM-DD hh24:mi')) diff_hours from dual;. Instead of: datediff ('QUARTER', pr. 25) AS `years`, COUNT(FLOOR(DATEDIFF(NOW(),`startdate`)/365. Here’s the syntax for the DATEADD function: DATEADD (interval, number, date); The interval. This is because the two dates are exactly 24 hours apart. Modified 2 years, 9 months ago. That prevents. It operates according to the rules of the Gregorian calendar. Hot. Improve this answer. The default is zero (0). 365 days elapse between the two dates. For example: print &order_date () edit 'Month dd, YYYY'. Multiply by 24 -- hours, multiply by 60 minutes, multiply by 60 -- seconds. You should consider how many. The expression is given to calculate the month’s difference between two dates, use the date diff expression as shown below. 32 illustrates the behaviors of the basic arithmetic operators ( +, *, etc. The key is to use DATEADD and DATEDIFF along with the appropriate SQL timespan enumeration. + (Concatenation) operator. I am trying to use the INTNX function to get the first and last days of the previous month. Then the 1 represents the first day of that month. 25)) AS `numberofemployees`. SQL date formatfunctions in SQL server are really powerful and really helps to deliver impactful data analytics and reports. Beneath the plainness of its name, it hides a little depth.